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0.05x^2-0.7x+0.5=0
a = 0.05; b = -0.7; c = +0.5;
Δ = b2-4ac
Δ = -0.72-4·0.05·0.5
Δ = 0.39
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.7)-\sqrt{0.39}}{2*0.05}=\frac{0.7-\sqrt{0.39}}{0.1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.7)+\sqrt{0.39}}{2*0.05}=\frac{0.7+\sqrt{0.39}}{0.1} $
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